What are the three consecutive odd integers such that the square of the first increased the product of the other two is 224

Oct 13, 2025 by thesweetdesigns.com 67 views

What are the three consecutive odd integers such that the square of the first increased the product of the other two is 224

In mathematics, problems involving consecutive integers often require a combination of algebraic and arithmetic techniques to solve. In this article, we will explore a specific problem that involves finding three consecutive odd integers that satisfy a particular condition. The condition states that the square of the first integer increased by the product of the other two integers is equal to 224. We will use algebraic manipulations and logical deductions to find the solution to this problem.

Let's denote the three consecutive odd integers as x, x+2, and x+4. Since they are consecutive odd integers, the difference between any two consecutive integers is 2. We are given that the square of the first integer increased by the product of the other two integers is equal to 224. Mathematically, this can be expressed as:

x^2 + (x+2)(x+4) = 224

To simplify the equation, we can expand the product of the two binomials:

x^2 + x^2 + 6x + 8 = 224

Combine like terms:

2x^2 + 6x + 8 = 224

Subtract 224 from both sides:

2x^2 + 6x - 216 = 0

We can solve the quadratic equation using the quadratic formula:

x = (-b ± √(b^2 - 4ac)) / 2a

In this case, a = 2, b = 6, and c = -216. Plugging these values into the formula, we get:

x = (-(6) ± √((6)^2 - 4(2)(-216))) / 2(2)

x = (-6 ± √(36 + 1728)) / 4

x = (-6 ± √1764) / 4

x = (-6 ± 42) / 4

We have two possible values of x:

x = (-6 + 42) / 4 = 36 / 4 = 9

x = (-6 - 42) / 4 = -48 / 4 = -12

We need to check if both solutions satisfy the original equation. Let's plug x = 9 into the equation:

x^2 + (x+2)(x+4) = 9^2 + (9+2)(9+4)

= 81 + 11(13)

= 81 + 143

= 224

This solution satisfies the equation. Now, let's plug x = -12 into the equation:

x^2 + (x+2)(x+4) = (-12)^2 + (-12+2)(-12+4)

= 144 + (-10)(-8)

= 144 + 80

= 224

This solution also satisfies the equation.

We have found two possible sets of three consecutive odd integers that satisfy the given condition. The sets are {9, 11, 13} and {-12, -10, -8}. Both sets satisfy the equation x^2 + (x+2)(x+4) = 224. We used algebraic manipulations and logical deductions to find the solution to this problem.

The three consecutive odd integers such that the square of the first increased the product of the other two is 224 are:

{9, 11, 13}
{-12, -10, -8}

To find the solution to this problem, we used algebraic manipulations and logical deductions. We can also use numerical methods or graphical methods to find the solution.
We can also modify the problem by changing the condition. For example, we can ask for the three consecutive odd integers such that the product of the first two integers increased by the square of the third integer is equal to 224.
We can also ask for the three consecutive odd integers such that the sum of the first two integers increased by the product of the third integer is equal to 224.
Q&A: What are the three consecutive odd integers such that the square of the first increased the product of the other two is 224

In our previous article, we explored a problem that involved finding three consecutive odd integers that satisfy a particular condition. The condition states that the square of the first integer increased by the product of the other two integers is equal to 224. We used algebraic manipulations and logical deductions to find the solution to this problem. In this article, we will answer some frequently asked questions related to this problem.

A: The three consecutive odd integers such that the square of the first increased the product of the other two is 224 are:

{9, 11, 13}
{-12, -10, -8}

A: We used algebraic manipulations and logical deductions to find the solution to this problem. We started by simplifying the equation x^2 + (x+2)(x+4) = 224. We then solved the quadratic equation using the quadratic formula.

A: The quadratic formula is a mathematical formula that is used to solve quadratic equations. It is given by:

x = (-b ± √(b^2 - 4ac)) / 2a

A: To use the quadratic formula to solve a quadratic equation, you need to plug in the values of a, b, and c into the formula. In this case, a = 2, b = 6, and c = -216. Plugging these values into the formula, we get:

x = (-(6) ± √((6)^2 - 4(2)(-216))) / 2(2)

x = (-6 ± √(36 + 1728)) / 4

x = (-6 ± √1764) / 4

x = (-6 ± 42) / 4

A: The possible values of x are:

x = (-6 + 42) / 4 = 36 / 4 = 9

x = (-6 - 42) / 4 = -48 / 4 = -12

A: To check if a solution satisfies the original equation, you need to plug the value of x into the equation and simplify. If the result is equal to 224, then the solution satisfies the equation.

A: Let's say we want to check if x = 9 satisfies the original equation. We plug x = 9 into the equation:

x^2 + (x+2)(x+4) = 9^2 + (9+2)(9+4)

= 81 + 11(13)

= 81 + 143

= 224

This solution satisfies the equation.

A: Some additional tips and variations for this problem include:

Using numerical methods or graphical methods to find the solution
Modifying the problem by changing the condition
Asking for the three consecutive odd integers such that the product of the first two integers increased by the square of the third integer is equal to 224
Asking for the three consecutive odd integers such that the sum of the first two integers increased by the product of the third integer is equal to 224

In this article, we answered some frequently asked questions related to the problem of finding three consecutive odd integers that satisfy a particular condition. We used algebraic manipulations and logical deductions to find the solution to this problem. We also provided some additional tips and variations for this problem.