The Integral of a Square Root Function

Oct 13, 2025 by thesweetdesigns.com 41 views

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Introduction

In calculus, integration is a fundamental concept used to find the area under curves and solve problems involving accumulation. One of the most common types of integrals is the definite integral, which is used to find the area between a curve and the x-axis. In this article, we will evaluate the integral of a square root function, specifically the integral of $\sqrt{3x + 4}$ .

The Integral of a Square Root Function

The integral of a square root function can be evaluated using various techniques, including substitution and integration by parts. However, in this case, we will use the substitution method to evaluate the integral.

Substitution Method

The substitution method involves replacing a part of the integral with a new variable, which simplifies the integral and makes it easier to evaluate. In this case, we will substitute $u = 3x + 4$ , which is a common substitution for square root functions.

u = 3x + 4
du = 3dx

Evaluating the Integral

Now that we have substituted $u = 3x + 4$ , we can rewrite the integral in terms of $u$ .

\int \sqrt{3x + 4} \, dx = \frac{1}{3} \int \sqrt{u} \, du

The integral of $\sqrt{u}$ is $\frac{2}{3}u^{\frac{3}{2}}$ , so we can evaluate the integral as follows:

\frac{1}{3} \int \sqrt{u} \, du = \frac{1}{3} \cdot \frac{2}{3}u^{\frac{3}{2}} + C

Back Substitution

Now that we have evaluated the integral in terms of $u$ , we need to back substitute to express the answer in terms of $x$ . We can do this by replacing $u = 3x + 4$ .

\frac{2}{9}(3x + 4)^{\frac{3}{2}} + C

Conclusion

Examples and Applications

The integral of a square root function has many applications in mathematics and physics. For example, it is used to find the area under curves and solve problems involving accumulation. It is also used in physics to find the work done by a force and the energy of a system.

Example 1

Find the area under the curve $y = \sqrt{x}$ from $x = 0$ to $x = 4$ .

\int_{0}^{4} \sqrt{x} \, dx = \left[ \frac{2}{3}x^{\frac{3}{2}} \right]_{0}^{4}

Example 2

Find the work done by a force $F(x) = \sqrt{x}$ from $x = 0$ to $x = 4$ .

W = \int_{0}^{4} F(x) \, dx = \int_{0}^{4} \sqrt{x} \, dx = \left[ \frac{2}{3}x^{\frac{3}{2}} \right]_{0}^{4}

Exercises

Evaluate the integral $\int \sqrt{2x + 1} \, dx$ .
Find the area under the curve $y = \sqrt{x}$ from $x = 0$ to $x = 9$ .
Find the work done by a force $F(x) = \sqrt{x}$ from $x = 0$ to $x = 9$ .

Solutions

$\int \sqrt{2x + 1} \, dx = \frac{1}{2} \int \sqrt{u} \, du = \frac{1}{2} \cdot \frac{2}{3}u^{\frac{3}{2}} + C = \frac{1}{3}(2x + 1)^{\frac{3}{2}} + C$
$\int_{0}^{9} \sqrt{x} \, dx = \left[ \frac{2}{3}x^{\frac{3}{2}} \right]_{0}^{9} = \frac{2}{3}(9)^{\frac{3}{2}} - 0 = 18$
$W = \int_{0}^{9} F(x) \, dx = \int_{0}^{9} \sqrt{x} \, dx = \left[ \frac{2}{3}x^{\frac{3}{2}} \right]_{0}^{9} = 18$

Conclusion

In this article, we evaluated the integral of a square root function using the substitution method. We substituted $u = 3x + 4$ and evaluated the integral in terms of $u$ . Finally, we back substituted to express the answer in terms of $x$ . The final answer is $\frac{2}{9}(3x + 4)^{\frac{3}{2}} + C$ . We also provided examples and applications of the integral of a square root function, including finding the area under curves and solving problems involving accumulation.

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Introduction

In our previous article, we evaluated the integral of a square root function using the substitution method. In this article, we will answer some common questions related to evaluating the integral of a square root function.

Q1: What is the integral of a square root function?

The integral of a square root function is a fundamental concept in calculus that is used to find the area under curves and solve problems involving accumulation. The integral of a square root function can be evaluated using various techniques, including substitution and integration by parts.

Q2: How do I evaluate the integral of a square root function?

To evaluate the integral of a square root function, you can use the substitution method. This involves replacing a part of the integral with a new variable, which simplifies the integral and makes it easier to evaluate.

Q3: What is the substitution method?

The substitution method is a technique used to evaluate integrals by replacing a part of the integral with a new variable. This simplifies the integral and makes it easier to evaluate.

Q4: How do I choose the substitution?

To choose the substitution, you need to identify a part of the integral that can be replaced with a new variable. This is usually a function that is raised to a power, such as a square root.

Q5: What is the integral of $\sqrt{3x + 4}$ ?

The integral of $\sqrt{3x + 4}$ is $\frac{2}{9}(3x + 4)^{\frac{3}{2}} + C$ .

Q6: How do I evaluate the integral of $\sqrt{2x + 1}$ ?

To evaluate the integral of $\sqrt{2x + 1}$ , you can use the substitution method. Let $u = 2x + 1$ , then $du = 2dx$ . The integral becomes $\frac{1}{2} \int \sqrt{u} \, du = \frac{1}{2} \cdot \frac{2}{3}u^{\frac{3}{2}} + C = \frac{1}{3}(2x + 1)^{\frac{3}{2}} + C$ .

Q7: What is the area under the curve $y = \sqrt{x}$ from $x = 0$ to $x = 4$ ?

The area under the curve $y = \sqrt{x}$ from $x = 0$ to $x = 4$ is $\left[ \frac{2}{3}x^{\frac{3}{2}} \right]_{0}^{4} = \frac{2}{3}(4)^{\frac{3}{2}} - 0 = 16/3$ .

Q8: How do I find the work done by a force $F(x) = \sqrt{x}$ from $x = 0$ to $x = 4$ ?

To find the work done by a force $F(x) = \sqrt{x}$ from $x = 0$ to $x = 4$ , you need to evaluate the integral $\int_{0}^{4} F(x) \, dx = \int_{0}^{4} \sqrt{x} \, dx = \left[ \frac{2}{3}x^{\frac{3}{2}} \right]_{0}^{4} = 16/3$ .

Q9: What are some common applications of the integral of a square root function?

The integral of a square root function has many applications in mathematics and physics, including finding the area under curves and solving problems involving accumulation.

Q10: How do I evaluate the integral of a square root function with a constant multiple?

To evaluate the integral of a square root function with a constant multiple, you can use the substitution method. Let $u = ax + b$ , then $du = adx$ . The integral becomes $\frac{1}{a} \int \sqrt{u} \, du = \frac{1}{a} \cdot \frac{2}{3}u^{\frac{3}{2}} + C = \frac{2}{3a}(ax + b)^{\frac{3}{2}} + C$ .

Conclusion

In this article, we answered some common questions related to evaluating the integral of a square root function. We provided examples and applications of the integral of a square root function, including finding the area under curves and solving problems involving accumulation.