Not considering the behavior of the function

Oct 13, 2025 by thesweetdesigns.com 146 views

Let's Explore the Domain and Inverse of a Quadratic Function

1. Introduction to the Problem

In this article, we will delve into the world of quadratic functions and explore the concept of one-to-one and non-decreasing functions. We will start by examining the given function $$f(x) = (x + 7)^2$$ and find a domain on which it is one-to-one and non-decreasing. Then, we will find the inverse of $$f$$ restricted to this domain.

2. Understanding One-to-One and Non-Decreasing Functions

A function is said to be one-to-one if it maps each element of its domain to a unique element in its range. In other words, no two distinct elements in the domain can map to the same element in the range. A function is said to be non-decreasing if for any two elements $$x_1$$ and $$x_2$$ in its domain, $$f(x_1) \leq f(x_2)$$ whenever $$x_1 \leq x_2$$.

3. Finding the Domain of $$f$$

To find the domain of $$f$$, we need to determine the values of $$x$$ for which $$f(x)$$ is defined. Since $$f(x) = (x + 7)^2$$, we can see that $$f(x)$$ is defined for all real numbers $$x$$. However, to find the domain on which $$f$$ is one-to-one and non-decreasing, we need to consider the behavior of the function.

4. Analyzing the Behavior of $$f$$

Let's analyze the behavior of $$f$$ by considering its graph. The graph of $$f$$ is a parabola that opens upwards, with its vertex at $$x = -7$$. Since the parabola opens upwards, the function is increasing for all $$x \geq -7$$ and decreasing for all $$x < -7$$.

5. Finding the Domain of $$f$$

Based on the analysis of the behavior of $$f$$, we can conclude that the domain of $$f$$ on which it is one-to-one and non-decreasing is $$x \geq -7$$.

6. Finding the Inverse of $$f$$

To find the inverse of $$f$$, we need to swap the roles of $$x$$ and $$y$$ and solve for $$y$$. Let's start by writing $$y = (x + 7)^2$$ and then swapping the roles of $$x$$ and $$y$$ to get $$x = (y + 7)^2$$.

7. Solving for $$y$$

Now, we need to solve for $$y$$. Taking the square root of both sides, we get $$\sqrt{x} = y + 7$$. Subtracting $$7$$ from both sides, we get $$y = \sqrt{x} - 7$$.

8. Simplifying the Inverse

However, we need to be careful when simplifying the inverse. Since the domain of $$f$$ is $$x \geq -7$$, we need to ensure that the inverse is also defined for this domain. Taking the square root of both sides, we get $$\sqrt{x} = y + 7$$. Since $$x \geq -7$$, we know that $$\sqrt{x} \geq 0$$. Therefore, we can simplify the inverse to $$y = \sqrt{x} - 7$$.

9. Conclusion

In conclusion, we have found the domain of $$f$$ on which it is one-to-one and non-decreasing to be $$x \geq -7$$. We have also found the inverse of $$f$$ restricted to this domain to be $$f^{-1}(x) = \sqrt{x} - 7$$.

10. Final Answer

The final answer is: $\boxed{\sqrt{x} - 7}$
Q&A: Let's Explore the Domain and Inverse of a Quadratic Function

Frequently Asked Questions

In this article, we will answer some of the most frequently asked questions related to the domain and inverse of a quadratic function.

Q: What is the domain of the function $$f(x) = (x + 7)^2$$?

A: The domain of the function $$f(x) = (x + 7)^2$$ is all real numbers $$x$$. However, to find the domain on which $$f$$ is one-to-one and non-decreasing, we need to consider the behavior of the function.

Q: Why is the function $$f(x) = (x + 7)^2$$ not one-to-one for all real numbers $$x$$?

A: The function $$f(x) = (x + 7)^2$$ is not one-to-one for all real numbers $$x$$ because it is decreasing for all $$x < -7$$ and increasing for all $$x \geq -7$$. This means that for any two distinct elements $$x_1$$ and $$x_2$$ in the domain, $$f(x_1)$$ and $$f(x_2)$$ can be equal even if $$x_1$$ and $$x_2$$ are not equal.

Q: What is the domain of $$f$$ on which it is one-to-one and non-decreasing?

A: The domain of $$f$$ on which it is one-to-one and non-decreasing is $$x \geq -7$$.

Q: How do we find the inverse of $$f$$?

A: To find the inverse of $$f$$, we need to swap the roles of $$x$$ and $$y$$ and solve for $$y$$. Let's start by writing $$y = (x + 7)^2$$ and then swapping the roles of $$x$$ and $$y$$ to get $$x = (y + 7)^2$$.

Q: How do we solve for $$y$$?

A: To solve for $$y$$, we need to take the square root of both sides of the equation $$x = (y + 7)^2$$. This gives us $$\sqrt{x} = y + 7$$. Subtracting $$7$$ from both sides, we get $$y = \sqrt{x} - 7$$.

Q: What is the inverse of $$f$$ restricted to the domain $$x \geq -7$$?

A: The inverse of $$f$$ restricted to the domain $$x \geq -7$$ is $$f^{-1}(x) = \sqrt{x} - 7$$.

Q: Why do we need to be careful when simplifying the inverse?

A: We need to be careful when simplifying the inverse because the domain of $$f$$ is $$x \geq -7$$. Taking the square root of both sides, we get $$\sqrt{x} = y + 7$$. Since $$x \geq -7$$, we know that $$\sqrt{x} \geq 0$$. Therefore, we can simplify the inverse to $$y = \sqrt{x} - 7$$.

Q: What is the final answer?

A: The final answer is $$f^{-1}(x) = \sqrt{x} - 7$$.

Common Mistakes to Avoid

When working with quadratic functions, it's easy to make mistakes. Here are some common mistakes to avoid:

Not considering the behavior of the function: When finding the domain of a quadratic function, it's essential to consider the behavior of the function. This will help you determine the domain on which the function is one-to-one and non-decreasing.
Not swapping the roles of $$x$$ and $$y$$: When finding the inverse of a function, it's crucial to swap the roles of $$x$$ and $$y$$. This will help you solve for $$y$$ and find the inverse of the function.
Not being careful when simplifying the inverse: When simplifying the inverse of a function, it's essential to be careful. This will help you ensure that the inverse is defined for the correct domain.

Conclusion

In conclusion, finding the domain and inverse of a quadratic function can be a challenging task. However, by following the steps outlined in this article, you can ensure that you find the correct domain and inverse. Remember to consider the behavior of the function, swap the roles of $$x$$ and $$y$$, and be careful when simplifying the inverse. With practice and patience, you'll become a pro at finding the domain and inverse of quadratic functions!