Expanding the Squared Term

Oct 13, 2025 by thesweetdesigns.com 87 views

Solving the Quadratic Equation: Uncovering the Values of b

In mathematics, quadratic equations are a fundamental concept that play a crucial role in various fields, including algebra, geometry, and calculus. These equations are characterized by a squared variable, and their solutions can be found using various methods, including factoring, the quadratic formula, and completing the square. In this article, we will delve into the world of quadratic equations and explore the values of b that satisfy the equation $3(2b+3)^2 = 36$ .

The given equation is a quadratic equation in the form of $3(2b+3)^2 = 36$ . To solve for b, we need to isolate the variable b and simplify the equation. The first step is to expand the squared term using the formula $(a+b)^2 = a^2 + 2ab + b^2$ . In this case, we have $(2b+3)^2 = (2b)^2 + 2(2b)(3) + 3^2$ .

Expanding the Squared Term

Using the formula, we can expand the squared term as follows:

$(2b+3)^2 = (2b)^2 + 2(2b)(3) + 3^2$ $(2b+3)^2 = 4b^2 + 12b + 9$

Now, we can substitute this expression back into the original equation:

$3(4b^2 + 12b + 9) = 36$

Simplifying the Equation

To simplify the equation, we can start by distributing the coefficient 3 to the terms inside the parentheses:

$12b^2 + 36b + 27 = 36$

Next, we can subtract 36 from both sides of the equation to get:

$12b^2 + 36b - 9 = 0$

Using the Quadratic Formula

The quadratic formula is a powerful tool for solving quadratic equations. It states that for an equation in the form of $ax^2 + bx + c = 0$ , the solutions are given by:

$x = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a}$

In our case, we have $a = 12$ , $b = 36$ , and $c = -9$ . Plugging these values into the quadratic formula, we get:

$b = \frac{-36 \pm \sqrt{36^2 - 4(12)(-9)}}{2(12)}$

Simplifying the Quadratic Formula

To simplify the quadratic formula, we can start by evaluating the expression inside the square root:

$36^2 - 4(12)(-9) = 1296 + 432 = 1728$

Next, we can simplify the expression under the square root:

$\sqrt{1728} = 12\sqrt{3}$

Now, we can substitute this expression back into the quadratic formula:

$b = \frac{-36 \pm 12\sqrt{3}}{24}$

Simplifying the Expression

To simplify the expression, we can start by dividing both the numerator and the denominator by 12:

$b = \frac{-3 \pm \sqrt{3}}{2}$

In conclusion, the values of b that satisfy the equation $3(2b+3)^2 = 36$ are given by:

$b = \frac{-3+2\sqrt{3}}{2}$ and $b = \frac{-3-2\sqrt{3}}{2}$

These values can be verified by plugging them back into the original equation. The quadratic formula is a powerful tool for solving quadratic equations, and it can be used to find the solutions to a wide range of equations.

The quadratic formula is a fundamental concept in mathematics, and it has numerous applications in various fields, including algebra, geometry, and calculus. In this article, we have explored the values of b that satisfy the equation $3(2b+3)^2 = 36$ using the quadratic formula. The solutions to this equation are given by:

$b = \frac{-3+2\sqrt{3}}{2}$ and $b = \frac{-3-2\sqrt{3}}{2}$

In conclusion, the quadratic formula is a powerful tool for solving quadratic equations. It can be used to find the solutions to a wide range of equations, and it has numerous applications in various fields, including algebra, geometry, and calculus. In this article, we have explored the values of b that satisfy the equation $3(2b+3)^2 = 36$ using the quadratic formula. The solutions to this equation are given by:

$b = \frac{-3+2\sqrt{3}}{2}$ and $b = \frac{-3-2\sqrt{3}}{2}$

These values can be verified by plugging them back into the original equation. The quadratic formula is a fundamental concept in mathematics, and it has numerous applications in various fields.
Quadratic Equation Q&A: Uncovering the Solutions

In our previous article, we explored the values of b that satisfy the equation $3(2b+3)^2 = 36$ using the quadratic formula. In this article, we will delve into the world of quadratic equations and answer some of the most frequently asked questions about quadratic equations.

Q: What is a quadratic equation?

A quadratic equation is a polynomial equation of degree two, which means that the highest power of the variable is two. It is typically written in the form of $ax^2 + bx + c = 0$ , where a, b, and c are constants, and x is the variable.

Q: How do I solve a quadratic equation?

There are several methods to solve a quadratic equation, including factoring, the quadratic formula, and completing the square. The quadratic formula is a powerful tool for solving quadratic equations, and it is given by:

$x = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a}$

Q: What is the quadratic formula?

The quadratic formula is a formula that is used to solve quadratic equations. It is given by:

$x = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a}$

Q: How do I use the quadratic formula?

To use the quadratic formula, you need to plug in the values of a, b, and c into the formula. The formula will then give you the solutions to the equation.

Q: What are the solutions to a quadratic equation?

The solutions to a quadratic equation are the values of x that satisfy the equation. They can be real or complex numbers.

Q: How do I determine the number of solutions to a quadratic equation?

The number of solutions to a quadratic equation depends on the discriminant, which is given by $b^2 - 4ac$ . If the discriminant is positive, the equation has two distinct solutions. If the discriminant is zero, the equation has one repeated solution. If the discriminant is negative, the equation has no real solutions.

Q: What is the discriminant?

The discriminant is a value that is used to determine the number of solutions to a quadratic equation. It is given by $b^2 - 4ac$ .

Q: How do I calculate the discriminant?

To calculate the discriminant, you need to plug in the values of a, b, and c into the formula $b^2 - 4ac$ .

Q: What are the applications of quadratic equations?

Quadratic equations have numerous applications in various fields, including algebra, geometry, and calculus. They are used to model real-world problems, such as the motion of objects, the growth of populations, and the behavior of electrical circuits.

Q: How do I use quadratic equations in real-world problems?

Quadratic equations can be used to model real-world problems by plugging in the values of the variables into the equation. The equation can then be solved to find the solutions.

In conclusion, quadratic equations are a fundamental concept in mathematics, and they have numerous applications in various fields. In this article, we have answered some of the most frequently asked questions about quadratic equations, including how to solve a quadratic equation, what is the quadratic formula, and how to use quadratic equations in real-world problems.

In conclusion, quadratic equations are a powerful tool for solving problems in various fields. They can be used to model real-world problems, and they have numerous applications in algebra, geometry, and calculus. By understanding quadratic equations, you can solve problems that involve quadratic equations and make informed decisions in various fields.

For more information on quadratic equations, please refer to the following resources:

The quadratic formula is a powerful tool for solving quadratic equations. It can be used to find the solutions to a wide range of equations, and it has numerous applications in various fields. In this article, we have explored the quadratic formula and answered some of the most frequently asked questions about quadratic equations. The quadratic formula is a fundamental concept in mathematics, and it has numerous applications in various fields.