Critical Numbers and Intervals of Increase and Decrease

Oct 13, 2025 by thesweetdesigns.com 92 views

Critical Numbers and Intervals of Increase and Decrease

In calculus, critical numbers are the values of the variable that make the derivative of a function equal to zero or undefined. These points are crucial in understanding the behavior of a function, as they can indicate the presence of local maxima or minima. In this article, we will explore the concept of critical numbers and intervals of increase and decrease for the given function $f(x) = x^3 + 3x^2 + 2$ .

Step 1: Find the Derivative of $f(x)$

To find the critical numbers of $f(x)$ , we first need to find its derivative. Using the power rule of differentiation, we get:

f'(x) = \frac{d}{dx} (x^3 + 3x^2 + 2) = 3x^2 + 6x

Step 2: Find the Critical Numbers

Critical numbers are the values of $x$ that make the derivative $f'(x)$ equal to zero or undefined. In this case, we need to solve the equation $f'(x) = 0$ :

3x^2 + 6x = 0

We can factor out $3x$ from the equation:

3x(x + 2) = 0

This gives us two possible solutions:

x = 0 \text{ or } x = -2

Therefore, the critical numbers of $f(x)$ are $x = 0$ and $x = -2$ .

Step 3: Determine the Intervals of Increase and Decrease

To determine the intervals on which $f(x)$ is increasing and decreasing, we need to examine the sign of the derivative $f'(x)$ on different intervals. We can use the critical numbers to divide the real number line into three intervals:

(-\infty, -2), (-2, 0), \text{ and } (0, \infty)

On the interval $(-\infty, -2)$ , we can choose a test point, say $x = -3$ , and evaluate the derivative:

f'(-3) = 3(-3)^2 + 6(-3) = 27 - 18 = 9 > 0

Since the derivative is positive, $f(x)$ is increasing on the interval $(-\infty, -2)$ .

On the interval $(-2, 0)$ , we can choose a test point, say $x = -1$ , and evaluate the derivative:

f'(-1) = 3(-1)^2 + 6(-1) = 3 - 6 = -3 < 0

Since the derivative is negative, $f(x)$ is decreasing on the interval $(-2, 0)$ .

On the interval $(0, \infty)$ , we can choose a test point, say $x = 1$ , and evaluate the derivative:

f'(1) = 3(1)^2 + 6(1) = 3 + 6 = 9 > 0

Since the derivative is positive, $f(x)$ is increasing on the interval $(0, \infty)$ .

In conclusion, the critical numbers of the function $f(x) = x^3 + 3x^2 + 2$ are $x = 0$ and $x = -2$ . The function is increasing on the intervals $(-\infty, -2)$ and $(0, \infty)$ , and decreasing on the interval $(-2, 0)$ .

The final answer is: $\boxed{0, -2}$
Critical Numbers and Intervals of Increase and Decrease: Q&A

In our previous article, we explored the concept of critical numbers and intervals of increase and decrease for the function $f(x) = x^3 + 3x^2 + 2$ . We found that the critical numbers of $f(x)$ are $x = 0$ and $x = -2$ , and that the function is increasing on the intervals $(-\infty, -2)$ and $(0, \infty)$ , and decreasing on the interval $(-2, 0)$ . In this article, we will answer some frequently asked questions about critical numbers and intervals of increase and decrease.

Q: What is the purpose of finding critical numbers?

A: Finding critical numbers is an important step in understanding the behavior of a function. Critical numbers can indicate the presence of local maxima or minima, which can be useful in optimization problems.

Q: How do I find the critical numbers of a function?

A: To find the critical numbers of a function, you need to find the derivative of the function and set it equal to zero. You then need to solve for the values of $x$ that make the derivative equal to zero.

Q: What is the difference between a critical number and a local maximum or minimum?

A: A critical number is a value of $x$ that makes the derivative of a function equal to zero or undefined. A local maximum or minimum is a point on the graph of a function where the function changes from increasing to decreasing or vice versa.

Q: Can a function have more than one critical number?

A: Yes, a function can have more than one critical number. In fact, most functions have multiple critical numbers.

Q: How do I determine the intervals on which a function is increasing or decreasing?

A: To determine the intervals on which a function is increasing or decreasing, you need to examine the sign of the derivative of the function on different intervals. You can use the critical numbers to divide the real number line into intervals and then choose a test point in each interval to evaluate the derivative.

Q: What is the significance of the intervals of increase and decrease?

A: The intervals of increase and decrease are important in understanding the behavior of a function. They can indicate the presence of local maxima or minima, which can be useful in optimization problems.

Q: Can a function be increasing on one interval and decreasing on another?

A: Yes, a function can be increasing on one interval and decreasing on another. In fact, most functions have multiple intervals of increase and decrease.

Q: How do I use critical numbers and intervals of increase and decrease in optimization problems?

A: Critical numbers and intervals of increase and decrease can be used in optimization problems to find the maximum or minimum value of a function. By identifying the critical numbers and intervals of increase and decrease, you can narrow down the possible solutions and find the optimal solution.

In conclusion, critical numbers and intervals of increase and decrease are important concepts in calculus that can be used to understand the behavior of a function. By finding the critical numbers and intervals of increase and decrease, you can identify the local maxima and minima of a function and use this information to solve optimization problems.

The final answer is: Critical numbers and intervals of increase and decrease are important concepts in calculus that can be used to understand the behavior of a function.