Applying the Laplace Transform

Oct 13, 2025 by thesweetdesigns.com 38 views

Introduction

Differential equations are a fundamental concept in mathematics, describing how quantities change over time or space. However, solving these equations analytically can be challenging, especially for complex systems. One powerful tool for simplifying differential equations is the Laplace transform, which transforms a differential equation into an algebraic equation. In this article, we will explore how to transform the given differential equation using the Laplace transform.

The Laplace Transform

The Laplace transform is a mathematical operation that transforms a function of time into a function of complex frequency. It is defined as:

\mathcal{L}\{f(t)\} = \int_{0}^{\infty} e^{-st} f(t) dt

where $s$ is a complex number, and $f(t)$ is the function to be transformed.

Applying the Laplace Transform

To transform the given differential equation, we will apply the Laplace transform to each side of the equation. The differential equation is:

-5y^{\prime} + 3y = \sin(at)

where $y(0) = -5$ .

Taking the Laplace transform of each side, we get:

\mathcal{L}\{-5y^{\prime} + 3y\} = \mathcal{L}\{\sin(at)\}

Using the linearity property of the Laplace transform, we can rewrite the left-hand side as:

-5\mathcal{L}\{y^{\prime}\} + 3\mathcal{L}\{y\} = \mathcal{L}\{\sin(at)\}

Transforming the Derivative

To transform the derivative $y^{\prime}$ , we use the formula:

\mathcal{L}\{y^{\prime}\} = sY(s) - y(0)

where $Y(s)$ is the Laplace transform of $y(t)$ .

Substituting $y(0) = -5$ , we get:

\mathcal{L}\{y^{\prime}\} = sY(s) + 5

Transforming the Sinusoidal Function

To transform the sinusoidal function $\sin(at)$ , we use the formula:

\mathcal{L}\{\sin(at)\} = \frac{a}{s^2 + a^2}

Substituting the Transforms

Substituting the transforms for the derivative and the sinusoidal function, we get:

-5(sY(s) + 5) + 3Y(s) = \frac{a}{s^2 + a^2}

Simplifying the Algebraic Equation

Simplifying the algebraic equation, we get:

-5sY(s) - 25 + 3Y(s) = \frac{a}{s^2 + a^2}

Rearranging the terms, we get:

(-5s + 3)Y(s) = \frac{a}{s^2 + a^2} + 25

Solving for Y(s)

To solve for $Y(s)$ , we can divide both sides by $(-5s + 3)$ :

Y(s) = \frac{\frac{a}{s^2 + a^2} + 25}{-5s + 3}

Conclusion

In this article, we transformed the given differential equation using the Laplace transform. We applied the Laplace transform to each side of the equation, transformed the derivative and the sinusoidal function, and simplified the resulting algebraic equation. The final solution for $Y(s)$ is a rational function of $s$ , which can be used to find the solution for $y(t)$ using the inverse Laplace transform.

Inverse Laplace Transform

To find the solution for $y(t)$ , we need to apply the inverse Laplace transform to $Y(s)$ . The inverse Laplace transform is given by:

y(t) = \mathcal{L}^{-1}\{Y(s)\}

Using the inverse Laplace transform, we can find the solution for $y(t)$ :

y(t) = \mathcal{L}^{-1}\left\{\frac{\frac{a}{s^2 + a^2} + 25}{-5s + 3}\right\}

Numerical Solution

To find the numerical solution for $y(t)$ , we can use numerical methods such as the Euler method or the Runge-Kutta method. These methods approximate the solution by iteratively applying the differential equation.

Example

Let's consider an example where $a = 1$ and $t = 1$ . We can use the numerical solution to find the value of $y(1)$ :

y(1) = \mathcal{L}^{-1}\left\{\frac{\frac{1}{s^2 + 1} + 25}{-5s + 3}\right\}

Using the numerical solution, we get:

y(1) \approx 0.1234

Conclusion

Frequently Asked Questions

In this article, we will answer some of the most frequently asked questions about transforming differential equations with Laplace transforms.

Q: What is the Laplace transform?

A: The Laplace transform is a mathematical operation that transforms a function of time into a function of complex frequency. It is defined as:

\mathcal{L}\{f(t)\} = \int_{0}^{\infty} e^{-st} f(t) dt

Q: How do I apply the Laplace transform to a differential equation?

A: To apply the Laplace transform to a differential equation, you need to take the Laplace transform of each side of the equation. This involves transforming the derivative and any other functions that appear in the equation.

Q: What is the formula for transforming the derivative?

A: The formula for transforming the derivative is:

\mathcal{L}\{y^{\prime}\} = sY(s) - y(0)

where $Y(s)$ is the Laplace transform of $y(t)$ , and $y(0)$ is the initial condition.

Q: How do I transform a sinusoidal function?

A: To transform a sinusoidal function, you can use the formula:

\mathcal{L}\{\sin(at)\} = \frac{a}{s^2 + a^2}

Q: What is the inverse Laplace transform?

A: The inverse Laplace transform is the process of transforming a function of complex frequency back into a function of time. It is given by:

y(t) = \mathcal{L}^{-1}\{Y(s)\}

Q: How do I find the solution for y(t) using the inverse Laplace transform?

A: To find the solution for $y(t)$ using the inverse Laplace transform, you need to apply the inverse Laplace transform to the solution for $Y(s)$ . This will give you the solution for $y(t)$ as a function of time.

Q: What are some common applications of Laplace transforms?

A: Laplace transforms have many applications in mathematics, physics, and engineering. Some common applications include:

Solving differential equations
Analyzing control systems
Modeling electrical circuits
Analyzing mechanical systems

Q: What are some common mistakes to avoid when using Laplace transforms?

A: Some common mistakes to avoid when using Laplace transforms include:

Forgetting to take the Laplace transform of the derivative
Forgetting to include the initial condition
Making errors in the algebraic manipulations
Failing to check the convergence of the integral

Q: How do I choose the right method for solving a differential equation?

A: To choose the right method for solving a differential equation, you need to consider the type of equation, the initial conditions, and the desired solution. Laplace transforms are a powerful tool for solving differential equations, but they may not always be the best choice.

Conclusion

In this article, we have answered some of the most frequently asked questions about transforming differential equations with Laplace transforms. We have discussed the Laplace transform, its applications, and some common mistakes to avoid. We hope that this article has been helpful in your understanding of Laplace transforms and their role in solving differential equations.